ସରଳୀକରଣ ପ୍ରଶ୍ନ ୧୬
ପ୍ରଶ୍ନ-
$\sqrt{\sqrt{2500}+\sqrt{961}}=(\text { ? })^{2}$
(1) 81
(2) 3
(3) 6561
(4) 9
(5) ଏହିମାନଙ୍କ ମଧ୍ୟରୁ କିଛି ନୁହେଁ
Show Answer
ସଠିକ ଉତ୍ତର: (2)
ସମାଧାନ: (2)
$?^{2}=\sqrt{50+31}=\sqrt{81}=9$
$\therefore ?=\sqrt{9}=3$
BETA
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